... perfect , since all graphs satisfy w ( G ) x ( G ) and a ( G ) ≤ k ( G ) . Notice also that the two conditions are dual in the sense that a graph satisfies the first condition if and only if its complement satisfies the second . The ...
... satisfies strong completeness if : VF € E , \ H € D ( F ) , 3t Є T , Vp crashed ( F ) , q € correct ( F ) , Vt't : p ... perfect and the strong failure detectors 7 and we introduce our almost perfect failure detector : Definition 5 ...
... perfect equality , the Lorenz Curve is identical to the line of perfect equality , and so area A equals zero , and the Gini index equals zero . If there is perfect inequality , the Lorenz Curve coincides with the horizon- tal axis and ...
Yoshitomo Baba. Moreover , if eRe is a right perfect ring , then R also satisfies ar [ e , g , f ] . Proof . Put B = { XfRf | rgRf ( eRg ) ≤ X ≤ gRf and | ( X / rgRf ( eRg ) ) fRf | < ∞ } . Then B ⊆ Ar [ e , g , f ] by Lemma 2.4.2 ...
... perfect ( anti- ) symmetric OF - bilinear form hr that satisfies the equation ( A.46 ) comes from a perfect hermitian pairing H on the right OD - module U with respect to the involution dd . As usual to hr there corresponds a Zp ...
... perfect monoids Definition 17.25 . A monoid S is called right perfect if every right S - act has a projective cover . Theorem 17.26 ( Isbell [ Isb71 ] ) . A monoid S is right perfect if and only if S satisfies the following two ...
... perfect matching . Let G be a graph of order 2n satisfying the Tutte condition . We may assume that G is connected ... satisfies the Tutte condition . If not , for some S ' V ' , o ( G ′ – S ′ ) > S ′ ] . Then , by the parity ...
... perfect ring . ( 2 ) R satisfies the descending chain condition on principal left ideals . ( 3 ) Every flat R - module is projective . ( 4 ) R contains no infinite set of orthogonal idempotents and every nonzero left R- module contains ...
... perfect matching ( proved implicitly by Frobenius [ 1912 , 1917 ] and explicitly by König [ 1916 ] ) . To see this ... satisfies : ( 35 ) x , ≥0 x ( d ( v ) ) = 1 ( eЄE ) ( VEV ) where ( v ) denotes the set of edges incident with ...
... perfect matching . Therefore , only the complete graph satisfies the requirement of saturated non - factorizability as that is the only graph to which no edge can be added . If G has an even number of vertices , then let S be defined as ...