Mar 23, 2022 ˇ It failed with the message: java.lang.UnsupportedOperationException: Json-smart provider does not support TypeRef! Use a Jackson or Gson based provider.
Dec 5, 2015 ˇ I am getting a big json document and i want to parse only some part of it to my java classes. I was thinking to use something like jsonpath to extract partial ...
... Json-smart provider does not support TypeRef! Use a Jackson or Gson based provider"); } private static class StringReader extends JsonReaderI<String> ...
UnsupportedOperationException: Json-smart provider does not support TypeRef! Use a Jackson or Gson based provider. 上一章：JsonPath 读取JSON文档 下一章 ...
Mar 19, 2023 ˇ //java.lang.UnsupportedOperationException: Json-smart provider does not support TypeRef! Use a Jackson or Gson based provider. 这个例子中，我 ...
Jan 8, 2024 ˇ Both Gson and Jackson are good options for serializing/deserializing JSON data, simple to use and well documented. Advantages of Gson:.
Missing: TypeRef! | Show results with:TypeRef!
Jul 27, 2022 ˇ 默认情况下，一个简单的对象映射器由MappingProvider SPI提供。JsonPath提供了默认的实现： JsonSmartMappingProvider。但是不能将json字符串转为POJO对象。
People also ask
Why use GSON instead of Jackson?
What is the difference between Google GSON and JSON simple?
What is Jackson vs JSON?
Which GSON methods are useful for implementing JSON?
Use the TypeAdapterFactory returned by this method when creating your Gson with GsonBuilder to have GSON support JsonSerializable types. Returns: A GSON ...
No information is available for this page. ˇ Learn why
Jan 18, 2016 ˇ I want to parse a JSON object once, and then JsonPath.read() xpath's from it. I started off with something like: private val gsonJsonProvider:
Missing: smart support TypeRef! Jackson
